Evaluate(Double,Int32) Method

In This Topic

Computes the curve derivatives at parametric value u.

Syntax

'Declaration
 
Public Overloads Function Evaluate( _
   ByVal u As Double, _
   ByVal d As Integer _
) As Vector3D()

public Vector3D[] Evaluate( 
   double u,
   int d
)

The derivatives array.

Example

The following code fragment demonstrates how to compute the first 2 derivatives of the curve at the parametric value [0.25].

Vector3D[] CK = myCurve.Evaluate(0.25, 2);
 
Vector3D C   = CK[0];
Vector3D Cu  = CK[1];
Vector3D Cuu = CK[2];

Dim CK() As Vector3D = MyCurve.Evaluate(0.25, 2)
 
Dim C As Vector3D = CK(0)
Dim Cu As Vector3D = CK(1)
Dim Cuu As Vector3D = CK(2)

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