Surface.Evaluate (Double, Double, Int32) Method
The following code fragment demonstrates how to compute the first 2 derivatives of
the surface at the parametric value [0.25, 0.5].
Vector3D[,] SKL = mySurf.Evaluate(0.25, 2); Vector3D S = SKL[0,0]; Vector3D Su = SKL[1,0]; Vector3D Sv = SKL[0,1]; Vector3D Suu = SKL[2,0]; Vector3D Suv = SKL[1,1]; Vector3D Svv = SKL[0,2];
This language is not supported or no code example is available.
Dim SKL(,) As Vector3D = MySurf.Evaluate(0.25, 0.5, 2) Dim S As Vector3D = SKL(0,0) Dim Su As Vector3D = SKL(1,0) Dim Sv As Vector3D = SKL(0,1) Dim Suu As Vector3D = SKL(2,0) Dim Suv As Vector3D = SKL(1,1) Dim Svv As Vector3D = SKL(0,2)
This language is not supported or no code example is available.